The correct statement about the magnetic properties of ${\left[\mathrm{Fe}(\mathrm{CN}{)}_6\right]}^{3-}$ and ${\left[{\mathrm{FeF}}_6\right]}^{3-}$ is $(\mathrm{Z}=26)$.

The electronic configuration of free ${\mathrm{Fe}}^{3+}$ ion is $3{\mathrm{d}}^5$, i.e

In ${\left[\mathrm{Fe}(\mathrm{CN}{)}_6\right]}^{3-}$, the configuration is

In ${\left[{\mathrm{FeF}}_6\right]}^{3-}$, the configuration is

Both the complexes contain unpaired electron (s). Hence, these are paramagnetic.