# The correct statement about the magnetic properties of ${\left[\mathrm{Fe}\left(\mathrm{CN}{\right)}_{6}\right]}^{3-}$ and  is $\left(\mathrm{Z}=26\right)$.

1. A

both are paramagnetic.

2. B

both are diamagnetic

3. C

${\left[\mathrm{Fe}\left(\mathrm{CN}{\right)}_{6}\right]}^{3-}$ is diamagnetic, ${\left[{\mathrm{FeF}}_{6}\right]}^{3-}$ is paramagnetic.

4. D

${\left[\mathrm{Fe}\left(\mathrm{CN}{\right)}_{6}\right]}^{3-}$ is paramagnetic, ${\left[{\mathrm{FeF}}_{6}\right]}^{3-}$ is diamagnetic.

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### Solution:

The electronic configuration of free ${\mathrm{Fe}}^{3+}$ ion is $3{\mathrm{d}}^{5}$, i.e

In ${\left[\mathrm{Fe}\left(\mathrm{CN}{\right)}_{6}\right]}^{3-}$, the configuration is

In ${\left[{\mathrm{FeF}}_{6}\right]}^{3-}$, the configuration is

Both the complexes contain unpaired electron (s). Hence, these are paramagnetic.

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