The correct statement about the magnetic properties of Fe(CN)63 and  FeF63 is (Z=26).

  1. A

    both are paramagnetic.

  2. B

    both are diamagnetic

  3. C

    Fe(CN)63 is diamagnetic, FeF63 is paramagnetic.

  4. D

    Fe(CN)63 is paramagnetic, FeF63 is diamagnetic.

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    Solution:

    The electronic configuration of free Fe3+ ion is 3d5, i.e

    In Fe(CN)63, the configuration is

    In FeF63, the configuration is

    Both the complexes contain unpaired electron (s). Hence, these are paramagnetic.

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