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The correct statement about the magnetic properties of ${[Fe (CN)_{6}]}^{3 -}$ and ${[{FeF}_{6}]}^{3 -}$ is $(Z = 26)$ .

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both are paramagnetic.

both are diamagnetic

{[Fe (CN)_{6}]}^{3 -}

is diamagnetic,

{[{FeF}_{6}]}^{3 -}

is paramagnetic.

{[Fe (CN)_{6}]}^{3 -}

is paramagnetic,

{[{FeF}_{6}]}^{3 -}

is diamagnetic.

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detailed solution

Correct option is A

The electronic configuration of free ${Fe}^{3 +}$ ion is $3 d^{5}$ , i.e

In ${[Fe (CN)_{6}]}^{3 -}$ , the configuration is

In ${[{FeF}_{6}]}^{3 -}$ , the configuration is

Both the complexes contain unpaired electron (s). Hence, these are paramagnetic.

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The correct statement about the magnetic properties of Fe(CN)63− and FeF63− is (Z=26).