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The decreasing order of the rate of the reaction ${CH}_{3} Br + {Nu}^{-} \to {CH}_{3} - Nu + {Br}^{-}$ with nucleophiles $({Nu}^{-}) A to D$ $[{Nu}^{-} = (A) {PhO}^{-}$ , $(B) {AcO}^{-}$ , ${HO}^{-},$ $(D) {CH}_{3} O^{-}]$

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a

B > D > C > A

b

D > C > A > B

c

D > C > B > A

d

A > B > C > D

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detailed solution

Correct option is B

The order acid-strength of the conjugate acids of the given bases is ${CH}_{3} OH < H_{2} O < PhOH < AcOH$ The base-strength of the given bases will be

${\underset{D}{{CH}_{3} O}}^{-} > \underset{C}{{OH}^{-}} > \underset{A}{{PhO}^{-}} > \underset{B}{{AcO}^{-}}$ The stronger the base, stronger the nucleophile, greater the rate of nucleophilic displacement.

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