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Q.

The density of a 10.0% by mass KCl solution in water is $1.06 g {cm}^{- 3}$ Its molarity is

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a

1.420M

b

1.489M

c

$1.420 mol {kg}^{- 1}$

d

$1.489 molkg$

answer is B.

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Detailed Solution

$M = \frac{(10 g / 74.5 g {mol}^{- 1})}{(100 g / 1.06 g {cm}^{- 3})} = 1.42 \times 10^{- 3} mol {cm}^{- 3} = 1.42 mol {dm}^{- 3}$

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