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The enthalpy change for the reaction CaCO3(s)CaO(s)+CO2(g) at 1000 K is 176k J mol1. The value of ΔU for the reaction will be 

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a
176 kJ mol1
b
184.3 kJ mol1
c
167.7 kJ mol1
d
180 kJ mol1

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detailed solution

Correct option is C

Δvg=1. 

Hence,

ΔU=ΔHΔvgRT=176kJmol1(1)8.314×103kJK1mol1(1000K)=(1768.314)kJmol1=167.7kJmol1

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