The equilibrium constant of the reaction H2O(g)+CO(g)⇌H2(g)+CO2(g), is 0.44 at 1259 K. The value of equilibrium constant of the reactionH2(g)+CO2(g)⇌H2O(g)+CO(g)will be

The equilibrium constant of the reaction $H_{2} O (g) + CO (g) ⇌ H_{2} (g) + {CO}_{2} (g)$ , is 0.44 at 1259 K. The value of equilibrium constant of the reaction
$H_{2} (g) + {CO}_{2} (g) ⇌ H_{2} O (g) + CO (g)$
will be

A
+ 0.44
B
2.27
C
$\sqrt{2.27}$
D
1.0 ~ 0.44 = 0.56

Solution:

$K_{new} = 1 / K_{old} = 1 / 0.44 = 2.27$

a number that represents the proportionality of the reactant and product concentrations at equilibrium in a reversible chemical reaction at a certain temperature.

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