The formula of spine! structure is AB₂ O₄ . If A²⁺ and B³⁺ just fit into the voids generated by the cubical-closest packing of O^2- ions (r = 126 pm), the sizes of A ²⁺ and B³⁺, respectively, are about
The compound BeO has zinc blende unit cell. If r(Be 2+) = 59 pm, r(0 2 -) = 126 pm and M(Be) = 9 g mor ', answer the following three questions

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52.3 pm, 28.4 pm

28.4 pm, 52.2 pm

72.7 pm, 89.1 pm

89.1 pm, 72.7 pm

answer is B.

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Detailed Solution

A²⁺ occupy tetrahedral voids and B ³⁺ occupy octahedral voids,

the sizes of A ²⁺ and B³⁺,are 28.4 pm, 52.2 pm respectively

hence r_A²⁺= 0.225 x 126 pm= 28.4 pm and r_B³⁺= 0.414 x 126 pm= 52.2 pm

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