The geometry of  ${\mathrm{XeOF}}_4$ by $\mathrm{VSEPR}$ theory is:

The valence electrons in ${\mathrm{XeOF}}_4$ are $42 (= 8 + 6 + 4 \mathrm{x} 7)$. These are distributed as follows.

There are 6 pairs of electrons around $\mathrm{Xe}$. Their orientations will be square bipyramidal. The geometry of ${\mathrm{XeOF}}_4$ is square pyramid as the lone pair of electrons occupy apical position