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Q.

The half life of C-14 is 5600 years. A sample of freshly cut wood from a tree contains 10 mg of C-14. The amount left in the sample after 50000 years is (a-x) x 100 . The value of $(a - x) \times 100$ is

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Detailed Solution

$t = \frac{2.303}{K} \log \frac{a}{a - x}$

K = $\frac{0.693}{t_{1 / 2}}$ = $\frac{0.693}{5600}$

$\log \frac{a}{a - x} = \frac{5000 \times 0.693}{5600 \times 2.303}$

(a-x) = 0.02mg

(a-x) $\times$ 100 = 0.02 $\times$ 100 =2mg

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The half life of C-14 is 5600 years. A sample of freshly cut wood from a tree contains 10 mg of C-14. The amount left in the sample after 50000 years is (a-x) x 100 . The value of a-x×100 is