The heat capacity of 12.0 g of helium is about

A
$12.47 {JK}^{- 1}$
B
$20.79 {JK}^{- 1}$
C
$20.1 J {mol}^{- 1}$
D
$37.41 {JK}^{- 1}$

Solution:

Amount of helium, $n = \frac{m}{M} = \frac{12 g}{4 g {mol}^{- 1}} = 3 mol$ . Heh um 1s monatomic gas. Its $C_{V, m} = (3 / 2) R$ Heat capacity, $C_{V} = n C_{V, m} = (3 mol) (3 / 2) R = (\frac{9}{2} mol) (8.314 {JK}^{- 1} {mol}^{- 1}) = 37.41 {JK}^{- 1}$

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