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Q.

The hybridization of N in  NO2+,NO3 and NH4+ respectively are

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a

sp,sp2,sp3

b

sp,sp3,sp2

c

sp2,sp,sp3

d

sp3,sp2,sp

answer is A.

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Detailed Solution

NO2+ has 16 valence electrons. There arrangement will be :o....- N = o.... Two pairs of electrons around N implies linear geometry involving sp hybridization. NO3 has 24 (= 5 x 3 x 6 + 1) valence electrons. These are arranged as   Question Image

There are three pairs of electrons around N. Its geometry will be trigonal planar and will result from sp2 hybridization. NH4+ has  sp3 hybridization.

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