The hybridization of N in  NO2+,NO3− and NH4+ respectively are

The hybridization of N in  NO2+,NO3 and NH4+ respectively are

  1. A

    sp,sp2,sp3

  2. B

    sp,sp3,sp2

  3. C

    sp2,sp,sp3

  4. D

    sp3,sp2,sp

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    Solution:

    NO2+ has 16 valence electrons. There arrangement will be :o....- N = o.... Two pairs of electrons around N implies linear geometry involving sp hybridization. NO3 has 24 (= 5 x 3 x 6 + 1) valence electrons. These are arranged as   

    There are three pairs of electrons around N. Its geometry will be trigonal planar and will result from sp2 hybridization. NH4+ has  sp3 hybridization.

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