The hydration of propyne in the presence of HgSO4/H2SO4 produces

  1. A

    CH3CHO

  2. B

    CH3CH2CHO

  3. C

    CH3COCH3

  4. D

    HCHO

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    Solution:

    The reaction is,

    CH3C=CHHgSO4/H2SO4+H2OCH3C=CHc                    OHHgSO4/H2SO4H2OCH3COCH3                     OH -H2OCH3C  -CH3                       OH

    Thus, The hydration of propyne in the presence of HgSO4/H2SO4 produces CH3COCH3.

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