The indicator constant of an indicator is $10^{- 4}$ . If pH of solution in which this indicator is present is 3.5, which of the following facts will be correct?

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

Ionized indicator is present in the larger amount

Both ionized and unionized indicator are present in equal amounts

Unionized indicator is present in the larger amount

Percentage of indicator present in ionized form cannot be predicted

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$HIn ⇌ H^{+} +$ + In; Since $pH < p K_{Hin}^{\circ},$ the solution contains larger $H^{+}$ than that obtained from ionization of $HIn$ alone. Hence, the above equilibrium is shift to left, thus more of unionized indicator is present.

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Get Expert Academic Guidance – Connect with a Counselor Today!