The main product in the dehydration of ethyl alcohol in the presence of $H_{2} {SO}_{4}$ at 413 K

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1, 2 - ethanediol

Ethene

Ethanal

Ethoxy ethane

answer is D.

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Detailed Solution

When ethanol reacts with conc.H2SO4 at 413 K, inter molecular dehydration takes place and the product formed is Ethoxy ethane.

$2 C_{2} H_{5} OH \overset{H_{2} {SO}_{4} at 140 ° C (413 K)}{⟶} C_{2} H_{5} - O - C_{2} H_{5} + H_{2} O$

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