The mass of 80% pure NaOH sample required to prepare 100 ml of 0.1 M solution is

  1. A

    0.4

  2. B

    0.5

  3. C

    0.04

  4. D

    0.05

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    Solution:

    M=wGMW×1000V (ml)×%purity100

    0.1 =w40×1000100×80100

    w=48=0.5 gm

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