Search for: The mass of sucrose to be added to 300 g of water to lower its vapour pressure by 1.0 mmHg at 25°C is (Given: p∗( water )=23.8mmHgThe mass of sucrose to be added to 300 g of water to lower its vapour pressure by 1.0 mmHg at 25°C is (Given: p∗( water )=23.8mmHgA249.9 gB329.4 gC215.2 gD342.2 g Register to Get Free Mock Test and Study Material Grade ---Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pmPlease indicate your interest Live ClassesRecorded ClassesTest SeriesSelf LearningVerify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:Since. p=x1p1 we getx1=pp1∗=23.8−1.023.8=0.958 Now x1=n1n1+n2=(300/18)mol(300/18)mol+m/342gmol−1Equating these two, we get(300/18)(300/18)+(m/342g)=0.958 or m={(300/18)(1−0.958)}(342g)0.958=249.89gRelated content Distance Speed Time Formula Refractive Index Formula Mass Formula Electric Current Formula Ohm’s Law Formula Wavelength Formula Electric Power Formula Resistivity Formula Weight Formula Linear Momentum Formula