# The maximum no. or electrons in phosphorous atom for which n + I + m = 3 will be :

1. A

6

2. B

5

3. C

4

4. D

3

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### Solution:

The electronic configuration is,

${P}_{1s}\to 1{s}^{2}2{s}^{2}2{p}^{6}3{s}^{2}3{p}^{3}$

Here, the total number of electron with n+m+l=3 can be given as

2 (for p with $±\frac{1}{2}$ spin), $+2$ (for 39 with $±\frac{1}{2}$spin)
$+1$ (for $3\mathrm{p}$ as it has only single electron)
5 electrons.

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