The maximum no. or electrons in phosphorous atom for which n + I + m = 3 will be :

The electronic configuration is,

$P_{1 s} \to 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{3}$

Here, the total number of electron with n+m+l=3 can be given as

2 (for p with $\pm \frac{1}{2}$ spin), $+ 2$ (for 39 with $\pm \frac{1}{2}$ spin)
$+ 1$ (for $3 p$ as it has only single electron)
5 electrons.

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