Q.

The minimum and maximum values of wavelength in the Lyman series of a H atom are, respectively



 

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a

 91.2 nm and 121.5 nm

b

364.3 nm and 653.4 nm

c

 41.2 nm and 102.6 nm

d

 9.12 nm and 121.5 nm

answer is B.

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Detailed Solution

For lyman series,
Maximum wavelength implies minimum transition energy which is for n2 =2→n1 =1,E=10.4eV.
Minimum wavelength implies maximum transition energy which is for n2 =∞→n1 =1,E=13.6eV.
Therefore,
λmax =hc/E min =121nm, 
λ min =hc/E max =91nm.

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