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The molar enthalpies of combustion of C2H2(g) C(graphite) and H2(g) and 1300,394 and 286 kJ mol1respectively. The standard enthalpy of formation of C2H2(g) is 

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a
226 kJ mol1
b
226 kJ mol1
c
620 kJ mol1
d
620 kJ mol1

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detailed solution

Correct option is A

It is given that

C2H2(g)+52O2(g)2CO2(g)+H2O(l)         ΔH1=1300kJmol1C( graphite )+O2(g)CO2(g)                ΔH2=394kJmol1H2(g)+12O2(g)H2O(l)               ΔH3=286kJmol1

Hence, for the equation

 2C(graphite) +H2(g)C2H2(g)ΔH=2ΔH2+ΔH3ΔH1=[2×394286+(1300)]kJmol1=226kJmol1

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