The molar mass of calcium nitrate as determined from the colligative properties is found to be 65.6 g mol-1, The degree of dissociation of the salt is

The molar mass of calcium nitrate as determined from the colligative properties is found to be $65.6 g {mol}^{- 1}$ , The degree of dissociation of the salt is

A
0.25
B
0.50
C
0.75
D
0.85

Solution:

We have

$\begin{array}{l} {Ca}_{3} {({NO}_{3})}_{2} ⇌ & {Ca}^{2 +} + 2 {NO}_{3}^{-} \\ c (1 - α) & c α c (2 α) \end{array}$

Total concentration $= c (1 - α) + c α + c (2 α) = c (1 + 2 α)$

$\frac{Theoretical molecular mass}{Observed molecular mass} = \frac{(1 + 2 α)}{1} \Rightarrow \frac{164}{65.6} = \frac{1 + 2 α}{1} \Rightarrow α = 0.75$

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