The molarity of a solution is M. To decrease the molarity of this solution to M/2 , then

  1. A
    Weight of the solute to be doubled       
  2. B
    Weight of the solvent to be doubled
  3. C
    Volume of the solvent to be doubled    
  4. D
    Volume of the solution to be doubled

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    Solution:

    Consider initial and final solutions as per dilution law.

    Assume concentration (M) and volume (V) for initial and final conditions as follows below.

                  Initial                   Final

                M1=M              M2=M/2

                   V1 =V             V2=?

    From dilution method,

              M1V1=M2V2

       V2=M1V1M2=M×VM2=2V

    Therefore, to decrease the molarity of the solution to one-half from initial ,

     Then the volume of solution must be doubled.

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