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Q.

The molarity of a solution is M. To decrease the molarity of this solution to M/2 , then

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a

Weight of the solute to be doubled       

b

Volume of the solvent to be doubled    

c

Weight of the solvent to be doubled

d

Volume of the solution to be doubled

answer is D.

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Detailed Solution

Consider initial and final solutions as per dilution law.

Assume concentration (M) and volume (V) for initial and final conditions as follows below.

              Initial                   Final

            M1=M              M2=M/2

               V1 =V             V2=?

From dilution method,

          M1V1=M2V2

   V2=M1V1M2=M×VM2=2V

Therefore, to decrease the molarity of the solution to one-half from initial ,

 Then the volume of solution must be doubled.

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