# The molarity of a solution is M. To decrease the molarity of this solution to $\text{M}/2$, then

1. A
Weight of the solute to be doubled
2. B
Weight of the solvent to be doubled
3. C
Volume of the solvent to be doubled
4. D
Volume of the solution to be doubled

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### Solution:

Consider initial and final solutions as per dilution law.

Assume concentration (M) and volume (V) for initial and final conditions as follows below.

Initial                   Final

${\text{M}}_{1}=\text{M}$              ${\text{M}}_{2}=\text{M}/\text{2}$

${\text{V}}_{2}=?$

From dilution method,

${\text{M}}_{1}{\text{V}}_{1}={\text{M}}_{2}{\text{V}}_{2}$

${\text{V}}_{2}=\frac{{\text{M}}_{1}{\text{V}}_{1}}{{\text{M}}_{2}}=\frac{\overline{)\text{M}}×\text{V}}{\frac{\overline{)\text{M}}}{2}}=2\text{V}$

Therefore, to decrease the molarity of the solution to one-half from initial ,

Then the volume of solution must be doubled.

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