The molecular formula of a commercial resin used for exchanging ions in water softening is C8H7SO3Na (molecular weight : 206). What would be the maximum uptake of Ca2+ ions by the resin when expressed in mole per gram resin?

The molecular formula of a commercial resin used for exchanging ions in water softening is $C_{8} H_{7} {SO}_{3} Na$ (molecular weight : 206). What would be the maximum uptake of ${Ca}^{2 +}$ ions by the resin when expressed in mole per gram resin?

A
1/103
B
1/206
C
2/309
D
1/412

Solution:

The exchanging reaction is $2 C_{8} H_{7} {SO}_{3} Na + {Ca}^{2 +} \to {(C_{8} H_{7} {SO}_{3})}_{2} Ca + 2 {Na}^{+}$ For one mole of ${Ca}^{2 +}$ ions, two moles of resin is required. Thus, the maximum uptake of ${Ca}^{2 +}$ ions will be $1 mol {Ca}^{2 +} / 2 mol$ resin =1 mole ${Ca}^{2 +} / (2 x 206) g$ resin $\equiv (1 / 412) mol {Ca}^{2 +} / g$ of resin

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