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The number of electrons present in the $l = 2$ orbital of Cr is

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Correct option is C

The electronic configuration of Cr is $(1 s)^{2} (2 s)^{2} (2 p)^{6} (3 s)^{2} (3 p)^{6} (3 d)^{5} (4 s)^{1}$ .

l = 2 for d-orbital.

Cr contains 3d orbital and the number of electrons in 3d orbital is 5.

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The number of electrons present in the l=2 orbital of Cr is