The number of electrons present in the l=2 orbital of Cr is

The number of electrons present in the l=2 orbital of Cr is

  1. A

    3

  2. B

    4

  3. C

    5

  4. D

    6

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    Solution:

    The electronic configuration of Cr is (1s)2(2s)2(2p)6(3s)2(3p)6(3d)5(4s)1.

    l = 2 for d-orbital. 

    Cr contains 3d orbital and the number of electrons in 3d orbital is 5.

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