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The osmotic pressure of a solution at $0^{0} C$ is 4 atm. What will be its osmotic pressure at 546 K under similar conditions ?

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detailed solution

Correct option is H

$\begin{array}{l} \frac{π_{1}}{π_{2}} = \frac{T_{1}}{T_{2}} \\ \frac{4}{π_{2}} = \frac{273}{546} \\ π_{2} = 8 atm \end{array}$

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detailed solution

Correct answer is 8

$\begin{array}{l} \frac{π_{1}}{π_{2}} = \frac{T_{1}}{T_{2}} \\ \frac{4}{π_{2}} = \frac{273}{546} \\ π_{2} = 8 atm \end{array}$

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The osmotic pressure of a solution at 00C is 4 atm. What will be its osmotic pressure at 546 K under similar conditions ?