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The oxide that gives $H_{2} O_{2}$ on treating with a dilute acid is

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PbO

{Na}_{2} O_{2}

{MnO}_{2}

{TiO}_{2}

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detailed solution

Correct option is B

${Na}_{2} O_{2}$ is the oxide that produces $H_{2} O_{2}$ when exposed to a weak acid. Hydrogen peroxide with diluted acids can only be produced by genuine peroxides that have a $- O - O -$ link.

${Na}_{2} O_{2} + H_{2} {SO}_{4} \to {Na}_{2} {SO}_{4} + H_{2} O_{2}$

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The oxide that gives H2O2 on treating with a dilute acid is