# The possible set of quantum numbers $\left(n,l,m,s\right)$ of the last electron of unipositive potassium ion :

1. A

$3,2,0,\frac{1}{2}$

2. B

$4,0,0,-\frac{1}{2}$

3. C

$4,1,0,-\frac{1}{2}$

4. D

None of these

FREE Lve Classes, PDFs, Solved Questions, PYQ's, Mock Tests, Practice Tests, and Test Series!

+91

Verify OTP Code (required)

### Solution:

From the given options their is no possible set of quantum numbers $\left(n,l,m,s\right)$ of the last electron of unipositive potassium ion.

The electronic configuration of potassium ion is,

It is observed that the last ${e}^{-}$ goes into 3p subshell

The value of the quantum number are, $n=3;l=1;m=-1,0,1;s=+\frac{1}{2},-\frac{1}{2}$.

Hence, the option D is correct.

## Related content

Join Infinity Learn Regular Class Program!