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The precipitate of $Al {(OH)}_{3}$ dissolves in $NaOH$ solution. It is due to the formation of

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Al {(H_{2} O)}_{4} (OH)_{2}^{+}

Al {(H_{2} O)}_{3} (OH)_{3}

Al {(H_{2} O)}_{2} (OH)_{4}^{-}

Al (OH)_{6}^{3 -}

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detailed solution

Correct option is C

$A l (O H)_{3}$ is dissolved in a solution of $NaOH$ to create the complex chemical below:

$A l (O H)_{3} + N a O H \to {[A l (H_{2} O)_{2} (O H)_{4}]}^{-}$

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The precipitate of Al(OH)3 dissolves in NaOH solution. It is due to the formation of