# The quantum numbers,  could represent a valence electron in which atom in its ground state?

1. A

$\mathrm{Fe}$

2. B

$\mathrm{In}$

3. C

$\mathrm{Pd}$

4. D

$\mathrm{Se}$

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### Solution:

Here,

$\begin{array}{l}n=1 l=0=\left(1\mathrm{s}\right)\\ n=2 l=0,1=\left(2\mathrm{s},2\mathrm{p}\right)\\ n=3 l=0,1,2=\left(3\mathrm{s},3\mathrm{p},3\mathrm{d}\right)\\ n=4 l=0,1,2,3=\left(4\mathrm{s},4\mathrm{p},4\mathrm{d},4\mathrm{f}\right)\end{array}$

designated by letters
$\mathrm{l}=0$ s orbital
$\mathrm{l}=1$ p orbital
$\mathrm{l}=2$ d orbital
$\mathrm{l}=3$ f orbital

$\mathrm{N}=4$ indicates that an atom is in its fourth phase
$\mathrm{l}=1$indicates P orbital .

So, here the P-block element is $\mathrm{Se}$.

Hence, the option D is correct.

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