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The quantum numbers, $n = 4, l = 1, m_{l} = 0$ could represent a valence electron in which atom in its ground state?

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detailed solution

Correct option is D

Here,

$\begin{array}{ll} n = 1 l = 0 = (1 s) \\ n = 2 l = 0, 1 = (2 s, 2 p) \\ n = 3 l = 0, 1, 2 = (3 s, 3 p, 3 d) \\ n = 4 l = 0, 1, 2, 3 = (4 s, 4 p, 4 d, 4 f) \end{array}$

designated by letters
$l = 0$ s orbital
$l = 1$ p orbital
$l = 2$ d orbital
$l = 3$ f orbital

$N = 4$ indicates that an atom is in its fourth phase
$l = 1$ indicates P orbital .

So, here the P-block element is $Se$ .

Hence, the option D is correct.

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The quantum numbers, n=4, l=1, ml=0 could represent a valence electron in which atom in its ground state?