The rate of a chemical reaction doubles for every 10° C rise of temperature. If the temperature is raised by 50 °C, the rate of reaction increases by about

A
64 times
B
10 times
C
24 times
D
32 times

Solution:

We will have

$\underset{(t_{1})}{r_{1}} ⟶ \underset{(t_{1} + 10^{\circ} C)}{2 r_{1}} ⟶ \underset{(t_{1} + 20^{\circ} C)}{4 r_{1}} ⟶ \underset{(t_{1} + 30^{\circ} C)}{8 r_{1}} ⟶ \underset{(t_{1} + 40^{\circ} C)}{16 r_{1}} ⟶ \underset{(t_{1} + 50^{\circ} C)}{32 r_{1}}$

In short, $r = 2^{5} r_{1} = 32 r_{1}$ .

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