The rate of a first order reaction is 0.01 mol/lit-sec at 10 min and 0.03 mole/lit-sec at 20 min. After intiation, Find the half life of the reaction. [Given log43=0.1238 ]

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    Solution:

    K=2.303tloga(ax)t=2010=10min; a=0.04; (ax)=0.03 K=2.30310log0.040.03K=2.30310log43t1/2=0.693K=0.6932.30310log(4/3)t1/2=0.6932.303×10×10.1238=24.2

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