# The rate of formation of   in the reaction $2{\mathrm{SO}}_{2}+{\mathrm{O}}_{2}\to 2{\mathrm{SO}}_{3}$is 100g min-1. Hence rate of disappearance of O2 is

1. A

2. B

3. C

4. D

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### Solution:

According to stoichiometric relation
$\begin{array}{l}\frac{-\mathrm{d}\left[{\mathrm{O}}_{2}\right]}{\mathrm{dt}}=\frac{+1}{2}\frac{\mathrm{d}\left[{\mathrm{SO}}_{3}\right]}{\mathrm{dt}}\\ \frac{-\mathrm{d}\left[{\mathrm{O}}_{2}\right]}{\mathrm{dt}}=\frac{1}{2}×\frac{100}{80}\\ \frac{-\mathrm{d}\left[{\mathrm{O}}_{2}\right]}{\mathrm{dt}}=\frac{5}{8}×32=20\mathrm{g}{\mathrm{min}}^{-1}\end{array}$

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