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The ratio of lowering of vapour pressure of 0.1M aqueous solutions of $KCl, {CuSO}_{4} and {Na}_{2} {SO}_{4} is$

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1: 2:3

2: 2:3

1:1:1

3: 2:1

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detailed solution

Correct option is B

0.1M KCl $\to$ 0.2 moles of ion $(KCl \to K^{+} + {Cl}^{-})$

$0.1 M {CuSO}_{4} \to 0.2 moles of ion ({CuSO}_{4} \to {Cu}^{2 +} + {SO}_{4}^{2 -})$ $0.1 M \to 0.3 moles of ion ({Na}_{2} {SO}_{4} \to 2 {Na}^{+} + {SO}_{4}^{2 -})$ Ratio of lowering of vapour pressure depends upon no. of moles of ions.

=0.2:0.2:0.3

$\Rightarrow 2 : 2 : 3$

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The ratio of lowering of vapour pressure of 0.1M aqueous solutions of KCl, CuSO4 and Na2SO4 is