The ratio of the highest to the lowest wave length of Lyman series is=_______

A
4:3
B
9 ;8
C
27 ; 5
D
16 ; 5

Solution:

$\frac{1}{λ} = R_{H} z^{2} [\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}]$ for highest wave length energy of wave is lowest and for lowest wave length the energy of wave is maximum which is series limit line for lyman series.

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