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The reaction H2O(g)+CO(g)H2(g)+CO2(g) is initiated with 1 mol of each of H2O and CO in a flask of volume 10 L. If at equilibrium 40 mass per cent of water reacts, the equilibrium constant of the reaction will be 

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a
0.66
b
0.55
c
0.44
d
0.22

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detailed solution

Correct option is C

Mass of water reacted =40g100g×18g=7.2g  Amount of water reacted =7.2g18gmol1=0.4mol

We will have H2O(g)+CO(g)    H2(g)+CO2(g)(10.4)mol (10.4)mol    0.4mol 0.4mol

Since Δvg=0 We will have Kc=Kn Hence

Kc=(0.4mol)(0.4mol)(0.6mol)(0.6mol)=0.44

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