# The relative lowering of vapour pressure of a solution containing 6 g of urea dissolved in 90 g of water is

1. A

0.0196

2. B

O.05

3. C

1.50

4. D

0.01

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### Solution:

Wt. of urea$={\mathrm{W}}_{1}=6\mathrm{g}$

GMW of urea$={\mathrm{M}}_{1}=60\mathrm{g}$

Wt of water$={\mathrm{W}}_{2}=90\mathrm{g}$

GMW of water$={\mathrm{M}}_{2}=18\mathrm{g}$

According to Raoult’s law.

$\mathrm{R}.\mathrm{L}.\mathrm{V}.\mathrm{P}=\frac{{\mathrm{W}}_{1}}{{\mathrm{M}}_{1}}×\frac{{\mathrm{M}}_{2}}{{\mathrm{W}}_{2}}$

$=\frac{6}{60}×\frac{18}{90}$

$=\frac{1}{50}$

=0.02(Near by)

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