Q.

The resistance of a solution is 200Ω when placed in a conductivity cell of cell constant 0.4cm−1.  If the molar conductivity of the solution is 20Scm2mol−1, the concentration of the solution will be

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a

10−3M

b

10−4M

c

0.01 M

d

0.1 M

answer is B.

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Detailed Solution

κ=Kcell R=0.4cm−1200Ω=2×10−3Scm−1

c=κΛm=2×10−3Scm−120.0Scm2mol−1=1.0×10−4molcm−3=1.0×10−4mol10−1dm−3=0.1moldm−3

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