The size of isoelectronic species-F-Ne and Na+is affected by :

  1. A

    nuclear charge (Z)

  2. B

    valence principal quantum number (n)

  3. C

    electron-electron interaction in the outer orbitals

  4. D

    none of the factors because their size is the same

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    Solution:

    Nuclear charge has an effect on the sizes of the isoelectronic species F-Ne, and Na+(Z). The attraction between the nucleus and the valence electrons will be stronger the higher the nuclear charge, and the ionic size will be smaller. As a result, F- has the largest ionic size while Na+ has the smallest.

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