The solubility of a sparingly soluble salt AB2, in water is 1.0 x 10-5 M. Its solubility product will be

The solubility of a sparingly soluble salt ${AB}_{2}$ , in water is $1.0 x 10^{- 5} M$ . Its solubility product will be

A
$1.0 X 10^{- 10} M^{3}$
B
$4 X 10^{- 15} M^{3}$
C
$4 X 10^{- 10} M^{3}$
D
$1 X 10^{- 15} M^{3}$

Solution:

$K_{sp} = [A^{2 +}] {[B^{-}]}^{2} = (1.0 \times 10^{- 5} M) {(2 \times 1.0 \times 10^{- 5} M)}^{2} = 4 \times 10^{- 15} M^{3}$

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