The species having smallest ionic radius is :

  1. A

    Al3+

  2. B

    Ba2+

  3. C

    K+

  4. D

    Mg2+

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    Solution:

    Ionic radius of Al3+ is equal to 53.
    Ionic radius of Ba2+ is equal to 135.
    Ionic radius of K+ is equal to 138.
    Ionic radius of Mg2+ is equal to 72.

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