The standard potentials of three metallic cations, X, Y and Z are 0.52, -0.03 and- 1.18 V, respectively. The order of reducing power of the corresponding metals is

A
$Y > Z > X$
B
$X > Y > Z$
C
$Z > Y > X$
D
$Z > X > Y$

Solution:

We have

$\begin{array}{ll} X^{+} + e^{-} = X; E^{\circ} = 0.52 V \\ Y^{+} + e^{-} = Y; E^{\circ} = - 0.03 V \\ Z^{+} + e^{-} = Z; E^{\circ} = - 1.18 V \end{array}] \begin{aligned} Reducing tendency \\ X^{+} > Y^{+} > Z^{+} \\ Oxidizing ability \\ X^{+} > Y^{+} > Z^{+} \end{aligned}$

$\begin{array}{ll} X \to X^{+} + e^{-}; E^{\circ} = - 0.52 V \\ Y \to Y^{+} + e^{-}; E^{\circ} = 0.03 V \\ Z \to Z^{+} + e^{-}; E^{\circ} = 1.18 V \end{array}] \begin{aligned} Oxidation tendency \\ Z > Y > X \\ reducing ability \\ Z > Y > X \end{aligned}$

Solution:

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