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The stoichiometry numbers of ${Cr}_{2} O_{7}^{2 -}, {CH}_{3} CHO, H^{+}$ in the balanced chemical equation of the reaction ${Cr}_{2} O_{7}^{2 -} + {CH}_{3} CHO + H^{+} ⟶ {Cr}^{3 +} + {CH}_{3} COOH + H_{2} O,$ respectively, are

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detailed solution

Correct option is C

The correct balanced chemical equation is,

$1 {Cr}_{2} O_{7}^{- 2} + 3 {CH}_{3} CHO + 8 H^{+} ⟶ 2 {Cr}^{3 +} + 2 {CH}_{3} COOH + 6 H_{2} O$

From the above equation it is observed that the stoichiometry numbers of ${Cr}_{2} O_{7}^{2 -}, {CH}_{3} CHO, H^{+}$ in the balanced chemical equation of the reaction are 1, 3, 8.

Hence the correct option is C.

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The stoichiometry numbers of Cr2O72−, CH3CHO, H+ in the balanced chemical equation of the reaction Cr2O72−+CH3CHO+H+⟶Cr3++CH3COOH+H2O, respectively, are