The structure of lF7 is - Infinity Learn

A
pentagonal bipyramid
B
square pyramid
C
trigonal bi pyramid
D
octahedral

Solution:

There are 56 (=7 + 7 x 7) valence electrons in ${IF}_{7}$ . There with be 7 pairs of electrons around iodine. These will be oriented in the directions of pentagonal bipryamid as shown in the following structure..

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