Solution:
There are 56 (=7 + 7 x 7) valence electrons in . There with be 7 pairs of electrons around iodine. These will be oriented in the directions of pentagonal bipryamid as shown in the following structure..
The structure of lF7 is
There are 56 (=7 + 7 x 7) valence electrons in . There with be 7 pairs of electrons around iodine. These will be oriented in the directions of pentagonal bipryamid as shown in the following structure..