The total kinetic energy of 0.6 mol of an ideal gas at 27 °C is

The total kinetic energy of 0.6 mol of an ideal gas at 27 °C is

  1. A

    1122 J

  2. B

    1681 J

  3. C

    2245 J

  4. D

    2806 J

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    Solution:

    Total kinetic energy =(0.6mol)328.314 J mol1K1(300K)=2245 J

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