The treatment of an ester with LiAlH4 followed by acid hydrolysis produces

  1. A

    two alcohols

  2. B

    two acids

  3. C

    two aldehydes

  4. D

    one molecule of alcohol and another of carboxylic acid

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    Solution:

    Two alcohols are produced. RCOORLiAlH4RCH2OH+ROH.

    The treatment of an open chain ester with LiAlH4 followed by acid hydrolysis produces two alcohols.
    For example, reduction of methyl acetate with lithium aluminum hydride produces methanol and ethanol.

    CH3COOCH3+4H+CH3CH2OH+CH3OH

    This reduction can also be carried out by using sodium in the presence of alcohol, or hydrogen gas in the presence of copper chromite catalyst under pressure at 200300C.

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