The value of pKio of water at 25 °C is about

The value of $p K_{i}^{o}$ of water at 25 °C is about

A
14.74
B
15.25
C
15.74
D
16.25

Solution:

For water,

$K_{i} = [H_{3} O^{+}] [{OH}^{-}] / [H_{2} O] K_{i} = (10^{- 7} M) (10^{- 7} M) / (55.56 M) K_{i} = 1.80 \times 10^{- 16} M$

Hence, $o K_{\circ}^{\circ} = - \log (K : / M) = - \log (1.80 \times 10^{- 16}) = 15.74$

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