The wavelength of light having wave number 400cm-1 is

The wavelength of light having wave number $400 {cm}^{- 1} is$

A
$2.5 μm$
B
$250 μm$
C
$25 μm$
D
$25 nm$

Solution:

The relation between wave number and wavelength is

$ϑ$ $= \frac{1}{λ}$

$\Rightarrow λ = \frac{1}{ϑ}$

$λ = \frac{1}{4000 {cm}^{- 1}} = 250 \times 10^{- 6} m$

$∴ 250 μm; since 1 μm = 10^{- 6} m$

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