ChemistryThe wavelength of the radiation emitted, when in a hydrogen atom electron falls from infinity to stationary state l, would be (Rydberg constant = 1.097×107m−1)

The wavelength of the radiation emitted, when in a hydrogen atom electron falls from infinity to stationary state l, would be (Rydberg constant = $1.097 \times 10^{7} m^{- 1}$ )

A
91 nm
B
192 nm
C
406 nm
D
$9.2 \times 10^{- 8} n m$

Solution:

We have $Δ \tilde{E} = R_{\infty} (\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}) = R_{\infty} (\frac{1}{l^{2}} - \frac{1}{\infty^{2}}) = R_{\infty}; λ = \frac{1}{\tilde{R_{\infty}}} = 0.91 \times 10^{- 7} m = 91 n m$

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