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Q.

The wavelength of the radiation emitted, when in a hydrogen atom electron falls from infinity to stationary state 1, would be:
(Rydberg constant $= 1.097 \times 10^{τ} m^{- 1}$ )

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a

$406 nm$

b

$192 nm$

c

$9.1 \times 10^{- 6} nm$

d

$91 nm$

answer is A.

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Detailed Solution

It is known that;

$\frac{1}{λ} = R_{H} [\frac{1}{1^{2}} - \frac{1}{\infty^{2}}]$

$\Rightarrow λ = 912 Å$

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