The weight of NaCl present  in 250 mL of 0.1 N solution is      

  1. A
    1.46 g 
  2. B
    2.93 g
  3. C
    5.86 g
  4. D
    0.73 g

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    Solution:

    The formula of normality is

    N=WGEW×1000V(mL)

    As per given data,

    N=0.1 N

    V=250 mL

    GEW =GMW1=58.51=58.5

    From normality,

    0.1=w58.5×10004250

    w=1.46 g

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