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Two moles of oxygen undergoes isothermal expansion from volume $10 {dm}^{3}$ to $20 {dm}^{3}$ against an external pressure of 2 atm. The work involved in this process is

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$- 1013.3 J$

$2026.5 J$

$1013.2 J$

$- 2026.5 J$

answer is D.

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Detailed Solution

$w = - p_{ext} (V_{2} - V_{1}) = - (2 \times 101.325 kPa) (20 {dm}^{3} - 10 {dm}^{3}) = - 2026.5 J$

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