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What is the percentage of deuterium in heavy water?

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detailed solution

Correct option is A

Heavy water=( $D_{2} O$ )

Molecular formula of heavy water $= {}_{1}^{2}H_{2} O (D_{2} O)$

M.Wt of heavy water=2(2)+16=20

% of deuterium= $\frac{wt of deuterium}{M . wt of heavy water} \times 100 = \frac{4}{20} \times 100 = 20 %$

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